from point C on one side of the river jackie chooses landmark B directly on the opposite bank. She then walks 50 ft upstream perpendicular to the line formed by B and C. She calls this point A and measures angle A to be 80 degrees. How far is it across the river?



????????????????????????????????????????????????????????

MATH???

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Let's see, so point A is 80degrees, and since its a right triangle (right opposite the bank), point C is 90degrees.

Which means point B is 10 degrees, since 180-90-80=10

We'll use law of sines, so 50/sin10 = x/sin80



...Wait, for some reason, i'm getting close to 283.5 feet. That can't be right....

Quote from: Wind-up Clock;1263787MATH???

what do you eat that with?

LAW OF SINES DOES NOT EXIST

sin10 = sin80
   50............BC

283.56 ft methinks

Quote from: Wind-up Clock;1263787MATH???

Let's see, so point A is 80degrees, and since its a right triangle, point C is 90degrees.

The last angle is 10 degrees then but im not sure where the 50 goes on the triangle and what formula im supposed to use and I don't have a text book

i think 50 is the length of the hypotenuse

Quote from: GodClock;1263792i think 50 is the length of the hypotenuse

yea thats where i put it on the paper, now im just not sure what other side I need because i dont feel like looking up both

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Checked it with calculator, it seems to be right, since

50/sin10 = 287.93

and

283.5/sin80 = 287.87

close enough, so the answer may be 283.5 feet

Quote from: GodClock;1263792i think 50 is the length of the hypotenuse

Nooo, she walked 50 feet from the right angle to the 80º angle. 50 is the length of the side connecting the two given angles, the hypotenuse is the side not touching the right angle.

It took 10 years to type this post on my wii

i love you guys and if you guys like doing math i have a bunch more problems you can do

Looking at this I'm thinking its going to be real shit going back to school this year

It's spring break damn it enough with the maths
Damn you Pre-Calc.

Quote from: Marlix Wright;1263801It's spring break damn it enough with the maths
Damn you Pre-Calc.

MY SPRING BREAK ENDED YESTERDAY AND THE CLASS IS 3RD TRACK TRIG OK

Quote from: PatriotClock;1263803MY SPRING BREAK ENDED YESTERDAY AND THE CLASS IS 3RD TRACK TRIG OK

IT CANT BE HARD IF ALL YOU'RE STRUGGLING WITH IS SIMPLE SOHCAHTOA EQUATIONS, PRE-CALC IS SHITTY HARD :l

Quote from: Marlix Wright;1263807IT CANT BE HARD IF ALL YOU'RE STRUGGLING WITH IS SIMPLE SOHCAHTOA EQUATIONS, PRE-CALC IS SHITTY HARD :l

IM THIRD TRACK WHICH MEANS I AM STUPID AT MATH.

ok now im doing Law of Cosines stuff which is easy

Law of sines is coming up after though

Ahh the simpler days of Trig...

Quote from: PatriotClock;1263812ok now im doing Law of Cosines stuff which is easy

Law of sines is coming up after though

I'm sorry but I think that a/sin(A) = b/sin(B) = c/sin(C)  
is easier than a² = b² + c² - bc.cos(A)

And my mother thinks this place makes me bad at math.





Pfft!

Quote from: ÛṕÐÃ...ŤĕĆĻōĉ₭;1263848I'm sorry but I think that a/sin(A) = b/sin(B) = c/sin(C)  
is easier than a² = b² + c² - bc.cos(A)

I dont

Man, we did that first semester, one of the easier parts because it was just all plugging in.